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Hi Anita, What you are trying to find is standard normal distribution where mean is 0 and the standard deviation is 1. We can convert any normally distributed population to standard normal distribution using z-scores. The z- score is z = (x-μ)/σ where For example: Find the z-score corresponding to a raw score of 132 from a normal distribution with mean 100 and standard deviation 15. z = (132-100)/15 = 32/15= 2.133 Our new raw score is 2.133. Hope this helps, Janice | ||||||||||||
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