A juggler tosses a ball into the air with a velocity of 40ft/sec from a height of 4 ft. Use s= -6t2 + vot+so to find how long it takes for the ball to return to the height of 4 ft.

I was wondering how should i start this out, and can you give me a brief explanation on the formula they ask you to use? thx

Hi David,

You are actually given the formula to find time: s= -6t^{2} + v_{o}t+s_{o}

s - distance at time t. In this case we want to find t when s = 4 ft

v_{o} - initial velocity is given to be 40 ft/s

s_{o} - initial distance is given to be 4 ft

Now it is just a matter of plugging the given information into the formula: