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No, you answer a different question: "How many six-letter words (not necessarily an English words) are there in which the last three letters are z's?'' If we switch the question to "How many six-letter words (not necessarily an English words) are there in which the last three letters are z's and there are no other z's?'', then the answer changes to 253 x 13. If we switch again to your question: "How many six-letter words (not necessarily an English words) are there in which exactly three of the letters are z's?'', then "pizazz'' becomes allowed. It means that the Claude | ||||||||||||
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Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences. |