I have 15 golfers playing 3 rounds of golf. We will be playing in fivesomes. Any formula that has everyone playing with a different person each round?

Thank you.
Dewey

Unfortunately, it cannot be done. Suppose in the first round the fivesomes are

ABCDE,abcde,12345

In the second round, A cannot play with B,C,D, or E. But then his fivesome must contain at least two of {a,b,c,d,e} or at least two of {1,2,3,4,5}. Thus even the second round will have some pair together again.

RD

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