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 Question from Neven: A woman raises a bucket of cement to a platform 40 ft above her head by means of a rope 80 ft long that passes over a pulley on the platform. If she holds her end of the rope firmly at head level and walks away at 5ft/s, how fast is the bucket rising when she is 30 ft away from the spot directly below the pulley? (G. F. Simmons, Calculus with Analytic Geometry, pg.142) Solution: 3ft/s I'm having trouble creating a usable diagram of the situation, and noticing geometric identities need to correctly write the function y(x) (answering the question - how does the height of bucket- above the reference point [head of lifter] depend on the change in horizontal position. Obviously the length of rope does not change, the rope position creates a right angle... but I cannot seem to be able to connect all this information together in a single expression at the moment. As usual, the calculus part is easy... it's setting the problem that's more difficult. Solve the problem and offer advice to combat such problems in the future! Thanks in advance!

Neven,

Here is my diagram

Using Pythagoras theorem on the triangle PQR gives

402 + x2 = (40 + y)2 .

Differentiate both sides with respect to time.

If you have difficulty completing the problem write back,
Penny

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