|
||||||||||||
|
||||||||||||
| ||||||||||||
Hi Rae, My understanding of this question is that someone has reported
And you want to determine the sample size the researcher used. You know that 18 out of 20 is a 90% confidence interval, z0.05 = 1.645 and the sample proportion was 0.75 so the calculation to obtain an error bound of ± 0.02 was Squaring both sides and solving for n gave me n = 1268.4. Harley | ||||||||||||
|
||||||||||||
Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences. |