



 
Renson, If (x,y) is a point on the line then x = 2y. If (x,y) is on the circle then (x,y) also satisfies the equation of the circle. Thus you can substitute x = 2y in the equation
to arrive at a quadratic in y which you can solve. For each y value find the corresponding x value using x = 2y. How many intersection points did you find? Harley  


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