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Robert, I labeled three points in the diagram you sent. Put a coordinate system on your diagram with the origin at O then the inside edge of the first gasket segment is part of the circle x2 + y2 = 282 and the outside edge is part of the circle x2 + y2 = 302. The x-coordinate of P is 39.5980/2 and hence the y-coordinate of P is given by y2 = 282 - (39.5980/2)2. Likewise Q has x-coordinate 39.5980/2 and hence the y-coordinate of Q is given by y2 = 302 - (39.5980/2)2. The distance you need, the distance between A and B is the distance between P and Q which is
which I get to be 2.7399 (inches I presume). Your diagram gives this as 1.4142 + 1.3297 = 2.7439 so we agree to 3 decimal places. I hope this helps. Write back if you need anything further, | ||||||||||||
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