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Hi Sandi, Let's graph it without the calculator, using the definition of absolute value. Hence if |x - 12| ≥ 0 then y= -5\12|x - 12| + 5 = y= -5\12 (x - 12) + 5 = -5/12 x + 5 + 5 = -5/12x + 10. If |x - 12| < 0 then y= -5\12|x - 12| + 5 = y= -5\12 [-(x - 12)] + 5 = 5/12 x - 5 + 5 = 5/12x. But |x - 12| ≥ 0 if x ≥ 12 and |x - 12| < 0 if x < 12 so Thus for x < 12 the graph is a straight line with slope 5/12 and passing through the origin. When x is close to 12 the value of the function is close to 5. When x ≥ 12 the slope changes to -5/12 and when x = 12 the value of the function is 5. Putting the two parts together gives Can you finish the problem now? Write back if you need more help, | ||||||||||||
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