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Hi Shirlyn, Here is my diagram. |AB| = 60 ft, |BC| = 80 ft, |FB| = y ft, |BG| = x ft and |EF| = a ft. Since triangles ABC and FBG are similar 60/80 = y/x and hence y = 3/4 x. |AF| = 60 - y ft and Pythagoras theorem tells us that |FG| = √(x2 + y2) ft. Triangles AFE and FBG are similar which allows you to find an expression for a × √(x2 + y2) in terms of x and y. But a × √(x2 + y2) is the area of the rectangle EFGD and now you can use the fact that y = 3/4 x to write the area of the rectangle in terms of x alone. Your knowledge of calculus now allows you to complete the problem. Penny | ||||||||||||
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