 |
| ||
| |||
|
| Math Central | Quandaries & Queries |
|
Question from venkatesh, a student: Q:)walking at 4/5 of his usual speed a man is 10 minutes too late .find his usual time. pls clear my confusion with above qsn.......im not getting answer.. |
Venkatesh,
I can help you get started.
Suppose his normal rate is r feet per minute and his normal time for the trip is t minutes. Since distance is equal to time times rate you know the distance he travels is r × t feet. You are told that is the rate is 4/5 × r feet per minute then the time to travel the same distance is t + 10 minutes.
I hope this helps,
Penny
| ||
| ||
| ||
 |
 |
|
Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences.