|
||||||||||||
|
||||||||||||
| ||||||||||||
Hi Alexea, Let the height of the rectangle by $y$ then the perimeter is $2x + 2y.$ In my diagram $ABC$ is a right triangle. What does Pythagoras tell you? Solve for $y$ in terms of $x.$ Substitute into the perimeter expression. Penny | ||||||||||||
|
||||||||||||
Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences. |