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 Angi, These are not easy problems. The web page "The social golfer problem", http://www.maa.org/editorial/mathgames/mathgames_08_14_07.html, gives the following schedule under which 24 golfers can play in foursomes for 7 days. I think that if you delete players O and V, and use days 1 through 6 only, then the schedule is exactly what you want. The thing happens if any 2 players belonging to the same foursome on day 7, and day 7 itself, are deleted. Day1 ABKU IJSE QRCM DGFX HLNO PTVW Enjoy!  | ||||||||||||
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