|
||||||||||||
|
||||||||||||
| ||||||||||||
Ginny, In my diagram P is the midpoint of BC. Triangles APC and ABP are congruent. Can you see why? This means that angle APC is a right angle and hence you can use the Theorem of Pythagoras to find |AP| which is the height of the triangle. Penny | ||||||||||||
|
||||||||||||
Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences. |