|
||||||||||||
|
||||||||||||
| ||||||||||||
Hi Hayley, Draw a diagram. I let the length of the rectangle be $L$ feet then the width must be $2 L$ feet. The area of a rectangle is the length times the width so $2 L \times L = 450$ square feet. Solve for $L.$ Penny | ||||||||||||
|
||||||||||||
Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences. |