



 
Hi Jeff, 10 can be factored as $10 \times 1$ or $2 \times 5$ and 6 can be factored as $6 \times 1$ or $2 \times 3.$ Let's try factoring 10 as $2 \times 5$ then the possible factorizations of $10x^2 + 17x  6$ are \[(5x \pm 3)(2x \pm 2)\] \[(5x \pm 2)(2x \pm 3)\] \[(5x \pm 6)(2x \pm 1)\] \[(5x \pm 1)(2x \pm 6)\] Since the constant term in the expression $10x^2 + 17x  6$ is negative you know that the factored form must have opposite signs. Expand the expressions above and see if any gives a middle term of $17x.$ If not then try again with the four possible factorization forms when 10 is factored as $10 \times 1.$ I hope this helps,  


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