



 
Hi Jessica, I am going to choose feet as the dimensions to use. Hence the depth of the border is $3$ inches which is $\frac{3}{12} = \frac14$ feet. The volume of the concrete (27 cubic feet) is the surface area times the depth so \[27 = \mbox{ surface area } \times \frac14.\] And hence the surface area of the concrete is $4 \times 27$ square feet. If the border is $d$ feet wide then the flower garden plus the border is $6 + 2d$ feet by $10 + 2d$ feet. The surface area of the concrete is then $(6 + 2d) \times (10 + 2d)$ square feet minus the surface area of the garden. Set this equal to $4 \times 27$ and solve for $d.$ Penny  


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