



 
Hi Karen, Every odd integer is 1 more than an even integer so every odd integer can be written 2n + 1 where n is some integer. The next odd integer is 2 more than 2n + 1 so its 2n + 1 + 2 = 2n + 3. The next odd integer is 2 more than 2n + 3 so three consecutive integers can be written
Now write the instruction "twice the sum of the second and the third is 43 more that three times the first" as an equation and solve for n. Penny  


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