|
||||||||||||
|
||||||||||||
| ||||||||||||
Hi Lenora, Let me try a different problem, $5 \frac23 - 2 \frac49.$ The integer part is, $5 - 2 = 3.$ When you subtract the fractions however you need a common denominator. $\frac23 = \frac{2 \times 3}{3 \times 3} = \frac69$ and hence \[\frac23 -\frac49 = \frac69 - \frac49 = \frac{6 - 4}{9} = \frac29\] and thus \[5 \frac23 - 2 \frac49 = 3 \frac29 \] Now try tour question, | ||||||||||||
|
||||||||||||
Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences. |