|
||||||||||||
|
||||||||||||
| ||||||||||||
Hi Megan, First you factor the $x^2 - a^2$ to get $(x - a)(x + a)$ and then you have \[\frac{(x - a)(x + a)}{xy} \times \frac{xy}{x + a}\] At this point you can cancel the $xy$ in the denominator of the first fraction with the $xy$ in the numerator of the second fraction. Likewise you can cancel the $(x + a)$ factor that occurs in both fractions. Penny | ||||||||||||
|
||||||||||||
Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences. |