|
||||||||||||
|
||||||||||||
| ||||||||||||
Hi Sussie, Factoring this expression gives \[y = x^2 - 2x - 3 = (x - 3)(x + 1).\] Hence the x-intercepts are $x = 3$ and $x = -1.$ Is this what you mean by the intercept form? Penny | ||||||||||||
|
||||||||||||
Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences. |