



 
Tom, I would start by finding the internal volume of the tank, $4.666 \times 3.5 \times 4.333 = 70.762$ cubic feet Salt water weighs 64 pounds per cubic foot so the weight of the salt water is $70.762 \times 64 = 4528.8$ pounds. Now find the external volume of the tank by adding 2 inches to the length, 2 inches to the width and 1 inch to the depth. (The tank has no top.) Subtract the internal volume to obtain the volume of iron in the tank. The density of the iron is $7.2 \times 64$ pounds per cubic foot so calculate the weight of the tank. I hope this helps,  


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