



 
Hi Balkees, I think your equation is \[ \frac34 (48x) = 2x\frac23 (612x)\] If this is correct then I think it is the fractions that are causing you difficulty, so let's get rid of them. The fraction on the right side has a denominator of $3$ so multiply each side of the equation by $3.$ The result is \[ 3 \times \frac34 (48x) = 3 \times \left(2x\frac23 (612x)\right)\] which simplifies to \[ \frac94 (48x) = 3 \times 2x 2 \times (612x)\] or \[ \frac94 (48x) = 6x (12  24 x)\] That's progress, one fraction is gone. Now multiply each side by $4.$ That will eliminate the second fraction. Solve for $x.$ Write back if you need more assistance,  


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