



 
Hi Christine, The key here is to use the fact that distance equals time times rate. Suppose that the faster car travels the distance $d$ kilometers to the end of the race in $t$ hours. Hence \[d = t \times 120.\] 20 minutes is one third of an hour so how long does it take the slower car to travel the same distance? Write this as an equation. Since $d$ is the same in both equations you can write one equation for $t.$ Solve for $t.$ What is $d?$ Penny  


Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences. 