|
||||||||||||
|
||||||||||||
| ||||||||||||
Cosmo, I am assuming that there are foursomes consisting of two A players and two B players. In that case, it would take 13 rounds for a particular A player to play once against each other A player as there are 13 opponents for each player. It would take 14 rounds to team with each B player once as there are 14 possible partners for each player. Under these assumptions what you want is not possible. Perhaps there is a way to vary the set-up some? Victoria | ||||||||||||
|
||||||||||||
Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences. |