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 Question from deepak, a student: There is pyramid on a base which is a regular hexagon of side 2a cm. If every slant edge of this pyramid is of length 5a/2 cm, than what will be the volume of this pyramid

The volume of a pyramid is $\large \frac13 \times \mbox{the area of the base } \times \mbox{the height}.$ (see the note at the end of our response to an earlier question.) Thus you need to find the area of a regular hexagon, and then use Pythagoras theorem twice to find the height.

Penny

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