Two ways, depending on whether you like trigonometry or quadratic equations better.
 Let one of the roots, $w,$ be $x+iy.$ Square it; what do you get? Now set the real part of that to 3, and the imaginary part to 4.
This gives a system of two secondorder equations; turn it into a single quadratic by algebra. You should get two solutions; they are the square roots.
 Convert to polar form: $r = \sqrt(3^2 + 4^2), \theta = \arctan(4/3).$ The radius of the square root is the square root of the original radius; the argument (angle) is half the original angle. As the original angle theta can also be thought of as $\theta + 2 \pi, \large \frac{\theta}{2} + \pi$ is also a square root; this is always the negative of the first one you found. Now convert back.
Good Hunting!
RD
