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| Math Central | Quandaries & Queries |
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Question from Emilee, a student: hi. How do i find the area of a triangle if the vertices are (-3,0) (-2,2) and (3,0). I graphed it and it came out a triangle. How do I find the area of it in an easy way? |
Hi Emilee,
I graphed it also.
The area of a triangle is $\large \frac12 \times \mbox{ base } \times \mbox{ height.}$ Your triangle is nicely placed with the base on the X-axis. What is the length of the base? What is the height of the triangle? What is its area?
I hope this helps,
Penny
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