



 
Hi Fatima, This doesn't look like it but these problems are about factoring, in particular about the difference of squares which says \[x^2  a^2 = (x + a)(x  a)\] The first problem your daughter is to solve is \[\frac{2}{x + 3} = \frac{1}{x^2  9}  \frac{1}{x  3}\] Since $x^2  9 = x^2  3^2 = (x + 3)(x  3),$ if you multiply both sides of the original equation by $x^3  9$ you should then be ably to solve the resulting equation for x. Penny  


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