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| Math Central | Quandaries & Queries |
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Question from Fatima, a parent: Tamika selects two different numbers at random from the set{8,9,10}and adds them. Carlos takes two different numbers |
Hi Fatima,
Tamika can select 8 and 9, 8 and 10 or 9 and 10, each with the same probability, $\large \frac13.$ What are the three sum Tamika can obtain? What are the three products Carlos can obtain?
There are thus 9 possible pairs of a sum and a product, each with the same probability. How many of them have the product greater than the sum?
Penny
Fatima wrote back
My doubt is that Iam getting only 6 possible Pairs
Please show me all the possible pairs
Thank you very much
Fatima,
If the three sums were a, b and c and the three products were p, q and r then the nine pairs are
ap; aq; ar; bp; bq; br; cp; cq; cr
Penny
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