



 
Hi Jenna, Let's try 2 different functions
To find $f(g(2))$ you first find $g(2).$
Thus $f(g(2)) = f(1) = \sqrt{1 + 1} = \sqrt{2}.$ To find $g(f(2))$ you need to find $f(2)$ first.
Now $g(f(2)) = g(\sqrt{3}) = 5  (\sqrt{3})^2 = 5  3 = 2.$ Now try your functions. Penny  


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