Jim,

There isn't a perfect schedule. In fact there really isn't a very good one. I wrote a program to check all of the possibilities. Here is the best solution it found:

Day 1 : (0, 0, 0, 1, 1, 1)
Day 2 : (0, 0, 1, 0, 1, 1)
Day 3 : (0, 0, 1, 1, 0, 1)
Day 4 : (0, 1, 0, 0, 1, 1)

The threesomes are numbered 0 and 1. The positions in the list are the players 1, 2, 3, 4, 5, 6. For example, on Day 3 the threesomes are 1,2,5 and 3,4,6.

Have some fun.
Victoria

Hi Harley,
I could not accurately follow the player line up by following the string of 0's and 1's. The player line up for days 1 and 3 are noted, but I could not figure out the player line up for days 2 and 4.

Can you help ?

Regards
Terry

Hi Terry,

Suppose the 6 golfers have names A, B, C, D, E and F. Each day they are divided into two threesomes, the "0" threesome and the "1" threesome. I labeled the columns of Victiria's table by the golfers names to get the following.

The 0's and 1's in the body of the table identify the threesomes. Notice that A is always in the "0" threesome and player F is always in the "1" threesome. For any other player read down his or her column. For example Player D is in the "1" threesome on days 1 and 3 and in the "1" threesome on days 2 and 4.

I hope this helps,
Penny