



 
Hi Joe, I would first multiply both sides of \[\frac{\cos 2\theta + \sin \theta 1}{\tan \theta} + \sin 2 \theta = \cos \theta\] by $\tan \theta.$ Next write $\cos 2 \theta, \sin 2 \theta \mbox{ and } \tan \theta$ in terms of $\sin \theta$ and $\cos \theta$ and then simplify. I hope this helps,  


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