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| Math Central | Quandaries & Queries |
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Question from joseph, a student: The perimeter of a rectangle is 72 inches. The length of the rectangle is three more than 2 times the width of the rectangle. What is the length of the rectangle? Write and solve an equation to determine the dimension of the rectangle. |
Hi Joseph,
Suppose the width of the rectangle is $w$ inches.
What is twice the width?
What is $3$ more than twice the width?
This is the length of the rectangle. The perimeter is twice the width plus twice the width. But you know the perimeter is 72 inches. Thus
(twice the width) + (twice the length) = 72 inches.
Solve this equation for $w.$
Penny
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