|
||||||||||||
|
||||||||||||
| ||||||||||||
Hi Kenya, There is no formal procedure or set of steps to solve problems like this, you just follow the clues that ar in the statements. Statements 1 and 3 are straightforward, the number is odd and less than 25. For statement 4 I would look at the prime factorization of $36.$ $ 36 = 2 \times 2 \times 3 \times 3.$ Thus the odd factors of $36$ are $3, 9$ and $1.$ Statement 2 is about arrays. From 9 tiles you can make 2 arrays, one 9 by 1 and the other 3 by 3. Thus 9 doesn't satisfy the condition in statement 1. From 3 tiles you can only make 1 array so 3 satisfies the conditions in all four statements. I expect that 3 is the answer expected to this problem although I would argue that 1 also satisfies all three conditions. Now try the other problems you sent us and, if you get stuck, write back to say what you have done and where you are stuck. Penny Kenya wrote back
120 and 240 are both correct answers to your first problem. For the second problem you are looking for a number that is a multiple of 2, a multiple of 4 and a multiple of 5. $2 \times 5 = 10$ is a multiple of $2$ and $5$ but not $4. \; 4 \times 5 = 20$ is a multiple of 2, 4 and 5 so $20$ is a correct answer. Is there another correct answer? Penny
| ||||||||||||
|
||||||||||||
Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences. |