



 
Here is what Kim sent. Hi Kim, In the next to the last line of what you sent you have mod6, I assume that is a typo and should be mod7. One of the challenges of working with modular arithmetic is that a question might have many different, correct answers. For example in your test is the true statement that $2 \equiv 9$(mod 7) but it is also true that $2 \equiv 16$(mod 7), $2 \equiv 23$(mod 7) and $2 \equiv 5$(mod 7). In fact 2 is equivalent to 2 plus or minus any multiple of 7, modulo 7. Hence the statement in the text that $3 + 18 \equiv 7$(mod 7) and your statement that $3 + 18 \equiv 0$(mod 7) are both true. It is conventional that when performing a calculation modulo 7, the answer be given as a number between 0 and 6 inclusive. Hence I would prefer your answer that $3 + 18 \equiv 0$(mod 7). For the same reason I would prefer the answer in the text that states $2 + 4 \equiv 6$(mod 7) to your, nevertheless true statement, that $2 + 4 \equiv 1$(mod 7). Harley  


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