



 
Hi Marlyn, I drew a diagram of what I think you are describing.$C$ is the centre of the circle, $AB$ is the rod, $D$ is the midpoint of $AB$ and $\theta$ is the measure of the angle $DCA.$ $ADC$ is a right triangle so \[\tan \theta = \frac{1.5}{6}= \frac14\] and hence \[\theta = \tan^{1} \frac14 = 14.036 \mbox{ degrees.}\] Hence the measure of the angle $BCA$ is very close to 28 degrees. Penny  


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