



 
Hi Mary, The function $h(t) = 0.6 t^2 + 72 t + 35$ is a parabola. Since the coefficient of $t^2$ is negative the parabola opens downward. I am not sure how you would determine at what value of $t$ this function reaches its maximum. If you know some calculus the differentiate $h(t)$ to obtain $h'(t)$ and then solve $h'(t) = 0$ for $t.$ If this is an algebra exercise then I expect that you know that for the parabola $y = a x^2 + b x + c$ the maximum (or minimum if $a$ is positive) occurs when $ x = \large \frac{b}{2a}.$ Whichever technique you use you will find that the maximum that $h(t)$ obtains is when $t = 60$ seconds. The maximum height will then be $h(60)$ feet. I really dislike this problem, it is completely ridiculous! Do you know anyone who can throw a ball upwards so that it takes a minute to reach its maximum height? Look at your value for $h(60).$ How many yards is that? How many football fields? Can you throw a ball that far? Harley  


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