



 
Hi again May, I can help get you started. Since the first digit $A$ is one quarter the last digit $D,$ $D$ must be 4 times $A.$ The only digits that are multiples of 4 are 0, 4 and 8 and hence $D = 4 \times A$ is 0, 4 or 8. What can $A$ be? Now use the fact that the second digit is one less than the first digit. Write back if you need more help,  


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