



 
Hi Michael, I would let the second number be $n$ so that the three numbers are $n  1, n \mbox{ and } n + 1.$ Now write the equation that corresponds to "the second number squared is equal to the first and third added together". Solve the equation for $n.$ you should get two solutions. Check that they are correct by squaring $n$ and seeing if it is equal to the sum of $n  1$ and $n + 1.$ Penny  


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