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Hi, The key to this problem is that if $k$ is any number then \[\frac{k}{-2} = \frac{-k}{2} = - \frac{k}{2} = - \frac{1}{2} \times k.\] Hence \[\frac{-16 \times 6}{-2} = - \frac12 \times -16 \times 6.\] Does this help? Penny | ||||||||||||
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