



 
Hi Noel, I want to introduce a new measurement of volume called a TANK. A TANK is the volume of tank A in liters. The water is flowing out of tank A into tank B at a constant rate. After 6 minutes, $\frac13$ of the volume of tank A has flowed into tank B. Thus the water is flowing at a rate of \[\frac{\frac13 \mbox{ TANK}}{6 \mbox{ minutes}}= \frac{1}{18} \frac{\mbox{TANK}}{\mbox{ minute}}.\] After a further $8$ minutes, that is in $6 + 8 = 14$ minutes, the amount that has flowed out is \[ \frac{1}{18} \frac{\mbox{TANK}}{\mbox{ minute}} \times 14 \mbox{ minutes} = \frac{7}{9} \mbox{TANK}. \] Hence the 2.4 liters remaining is $\large \frac29 \mbox{ TANK}.$ How big is a TANK? What is the capacity of tank B? Penny  


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