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 Question from ankit, a student: integration from 0 to 2pi of 1/(3cos x + 2) dx

Hi Ankit,

The function $3 \cos x + 2$ is zero for two values of $x$ between  and $2 \pi.$

Go to Wolfram alpha and type in

integrate 1/(3 cos(x) + 2) from 0 to 2 pi

to see a graph of the integrand and more on this integral.

Harley

Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences.