



 
Hi Bailey, I can help get you started. Look at the first factor \[6a^2  5a + 1.\] $6$ can be factored as $6 \times 1$ or $3 \times 2$ and hence, if $6a^2  5a + 1$ can be factored it is \[6a^2  5a + 1 = (6a \pm \mbox{?})(a \pm \mbox{?})\] or \[6a^2  5a + 1 = (3a \pm \mbox{?})(2a \pm \mbox{?}).\] $1$ factors as $1 \times 1$ and hence the question marks are all $1.$ Since the constant term is positive and the middle term $(5a)$ is negative the signs must be negative and hence if $6a^2  5a + 1$ can be factored it is \[6a^2  5a + 1 = (6a  1)(a 1)\] or \[6a^2  5a + 1 = (3a 1)(2a 1).\] Which one gives a middle term of $5a?$ Now you factor $(8a^26a+1)$ and $(12a^27a+1).$ Penny  


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