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Brad, The bad news is that what you want isn't possible. On the first day there are three foursomes. On the second day, in each foursome, some two will have played together on the first day. The good news is that they did not need to be partners on the first day. There are 6 possible pairings in a foursome, and you are using four of them on a given day. Won't the handicaps (if honest) sort out the scoring? My suggestion is to make a schedule to get the pairings as good as possible, and then assign numbers to the players at random. If you don't like the assignment, do it a few times and choose the best one. --Victoria | ||||||||||||
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