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| Math Central | Quandaries & Queries |
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Question from Brian: the base of my triangle is 12 metres and the two sides are 8.45 metres |
Hi Brian,
In my diagram D is the midpoint of the base $BC.$
The angle $ADC$ is a right angle. Do you see why? Thus $|AD|$ is the height of the triangle. Pythagoras tell you the rest.
Penny
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