



 
Hi Charles, I agree with your calculation. The wedge to be removed sits on an arc of length 286.479 (inches?). You didn't include units.When you roll up the wedge to form a cone the slant height of the cone is the radius of the "round" and the radius of the circular base is half its diameter. I let the height be $h$ inches and then the triangle in the diagram is a right triangle so Pythagoras Theorem gives you \[h^2 + \left( \frac{38.19719}{2} \right)^2 = 24^2 .\] Thus \[h = \sqrt{24^2  \left( \frac{38.19719}{2} \right)^2} = 14.534 \mbox{ inches.}\] Harley  


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