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| Math Central | Quandaries & Queries |
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Question from Chelsea (81 to the power of 3n+2 over 243 to the power of -n) is equal to 3 to the power of 4 |
Hi Chelsea,
I also get $- \frac{4}{17}.$
$243 = 3^5$ and $81 = 3^4$ so
\[\frac{81^{3n + 2}}{243^{-n}}\]
becomes
\[\left( 3^4 \right)^{3n + 2} \times \left( 3^5 \right)^n = 3^4\]
Is that what you did?
Penny
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