



 
Hi Fahmie, The second equation can be rewritten $y = \frac12 x^2 + 4$ so it is a parabola that opens downward. When $x = 0$ what is $y?$ When $y = 0$ what is $x?$ Sketch its graph. The first equation is a circle. What is its radius? What is its center? Plot its graph. To solve the equations solve the second equation for $x^2,$ substitute into the first equation and solve for $y.$ Penny  


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