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 Question from fahmie, a student: graph and solve the intersection of the following equations: x^2+y^2=4 x^2+2y=4

Hi Fahmie,

The second equation can be rewritten $y = -\frac12 x^2 + 4$ so it is a parabola that opens downward. When $x = 0$ what is $y?$ When $y = 0$ what is $x?$ Sketch its graph.

The first equation is a circle. What is its radius? What is its center? Plot its graph.

To solve the equations solve the second equation for $x^2,$ substitute into the first equation and solve for $y.$

Penny

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