



 
Hi Jenna, I assume you are to solve for $y.$ I would eliminate the fractions to start with. To do this multiply both sides b4 $3 \times 2 = 6.$ this gives \[6 \times \frac{2y + 1}{3} = 6 \times \frac{1y  1}{2}\] which simplifies to \[2 \times (2y + 1) = 3 \times (y  1)\] Can you complete it from here? Write back if you need more assistance,  


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